n^2-17n+56=0

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Solution for n^2-17n+56=0 equation: 



n^2-17n+56=0

a = 1; b = -17; c = +56;
Δ = b2-4ac
Δ = -172-4·1·56
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{65}}{2*1}=\frac{17-\sqrt{65}}{2}
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{65}}{2*1}=\frac{17+\sqrt{65}}{2}
$

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